TV
Algorithms (3)
D' U' 2L2 U 2R' U' 2L2 U 2R D
My choice
14 HTM · 10 STM · 18 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 6 solvers' sheets
U' B' 2L' B 2R' B' 2L B 2R U
14 HTM · 10 STM · 14 QTM
rotationless
<U,R,L,B>
One hand: needs L, B, S or E
Cubemuch
U' 2R U' 2F2 U 2R' U' 2F2 U2
13 HTM · 9 STM · 18 QTM
3-gen
rotationless
<U,R,F>
One hand: R, U and M with F or D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: U' 2R' B' 2L' B 2R B' 2L B U. Every algorithm above was run by our logic engine from that state and reaches "solved".