TW
Algorithms (3)
D2 U' 2L2 U 2R' U' 2L2 U 2R D2
My choice
14 HTM · 10 STM · 20 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 6 solvers' sheets
U' 2B2 2L' B' 2L 2B2 2L' B 2L U
16 HTM · 10 STM · 20 QTM
3-gen
rotationless
<U,L,B>
One hand: needs L, B, S or E
Cubemuch
D2 2R B' 2L B 2R' B' 2L' B D2
14 HTM · 10 STM · 16 QTM
rotationless
<R,D,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: U' 2L' B' 2L 2B2 2L' B 2L 2B2 U. Every algorithm above was run by our logic engine from that state and reaches "solved".