TU
Algorithms (3)
U' 2L2 U 2R' U' 2L2 U 2R
My choice
12 HTM · 8 STM · 16 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 8 solvers' sheets
Lw U' 2L U 2R' U' 2L' U 2R Lw'
14 HTM · 10 STM · 14 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
2R B' 2L B 2R' B' 2L' B
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<R,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: Lw 2R' U' 2L U 2R U' 2L' U Lw'. Every algorithm above was run by our logic engine from that state and reaches "solved".