SJ
Algorithms (3)
2R U' 3L U 2R' U' 3L' U
My choice
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 3 solvers' sheets
2R U' 3R' U 2R' U' 3R U
12 HTM · 8 STM · 12 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
Cubemuch
2R 3Uw' 3L 3Uw 2R' 3Uw' 3L' 3Uw
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: U' 3R' U 2R U' 3R U 2R'. Every algorithm above was run by our logic engine from that state and reaches "solved".