SI
Algorithms (3)
F2 2D2 3L' U 3L 2D2 3L' U' 3L F2
My choice
16 HTM · 10 STM · 22 QTM
rotationless
<U,F,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
F 2R U' 3L U 2R' U' 3L' U F'
14 HTM · 10 STM · 14 QTM
rotationless
<U,R,F,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
2U' 3L U' 3L 2U 3L' U 3L 2U' 3L2 2U
20 HTM · 11 STM · 22 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: F U' 3L U 2R U' 3L' U 2R' F'. Every algorithm above was run by our logic engine from that state and reaches "solved".