SH
Algorithms (3)
3Uw' U' 2L' U 3L U' 2L U 3L' 3Uw
My choice
14 HTM · 10 STM · 14 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
3Lw U' 3R' 2U' 3R U 3R' 2U 3R 3Lw'
16 HTM · 10 STM · 16 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
Cubemuch
Rw 3Rw' 2B 3Rw 3D 3Rw' 2B' 3Rw 3D' Rw'
14 HTM · 10 STM · 14 QTM
3-gen
rotationless
<R,D,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3Lw 3R' 2U' 3R U' 3R' 2U 3R U 3Lw'. Every algorithm above was run by our logic engine from that state and reaches "solved".