SK
Algorithms (3)
2D2 3L' U 3L 2D2 3L' U' 3L
My choice
14 HTM · 8 STM · 18 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
3L U' 3L 2U2 3L' U 3L 2U2 3L2
16 HTM · 9 STM · 22 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
B U 3R U' 2R' U 3R' U' 2R B'
14 HTM · 10 STM · 14 QTM
3-gen
rotationless
<U,R,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3L2 2U2 3L' U' 3L 2U2 3L' U 3L'. Every algorithm above was run by our logic engine from that state and reaches "solved".