LT
Algorithms (3)
2L' U2 2L 3D2 2L' U2 2L 3D2
My choice
14 HTM · 8 STM · 20 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 4 solvers' sheets
B U 3R' U 2L' U' 3R U 2L U2 B'
15 HTM · 11 STM · 16 QTM
rotationless
<U,R,L,B>
One hand: needs L, B, S or E
Cubemuch
3D2 F 2R F' 3D2 F 2R' F'
12 HTM · 8 STM · 16 QTM
3-gen
rotationless
<R,F,D>
One hand: R, U and M with F and D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: B U2 2L' U' 3R' U 2L U' 3R U' B'. Every algorithm above was run by our logic engine from that state and reaches "solved".