LS
Algorithms (3)
U' 3L U' 2L' U 3L' U' 2L U2
My choice
13 HTM · 9 STM · 14 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
F' 3L' U 3L 2D2 3L' U' 3L 2D2 F
16 HTM · 10 STM · 20 QTM
rotationless
<U,F,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
U' 3R' U' 2L' U 3R U' 2L U2
13 HTM · 9 STM · 14 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: F' 2D2 3L' U 3L 2D2 3L' U' 3L F. Every algorithm above was run by our logic engine from that state and reaches "solved".