LU
Algorithms (3)
U' 3L2 U' 2L' U 3L2 U' 2L U2
My choice
13 HTM · 9 STM · 18 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
3D2 U' 3L2 U 2R' U' 3L2 U 2R 3D2
16 HTM · 10 STM · 24 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
U' 3R2 U' 2L' U 3R2 U' 2L U2
13 HTM · 9 STM · 18 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3D2 2R' U' 3L2 U 2R U' 3L2 U 3D2. Every algorithm above was run by our logic engine from that state and reaches "solved".