VX
Algorithms (3)
3Lw B U' 2L U 2R2 U' 2L' U 2R2 B' 3Lw'
My choice
16 HTM · 12 STM · 20 QTM
rotationless
<U,R,L,B>
One hand: needs L, B, S or E
Cubemuch
U 3Lw D 2R2 D 2L' D' 2R2 D 2L D2 3Lw' U'
17 HTM · 13 STM · 22 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
Cubemuch
Lw U2 D 2L D' 2F2 D 2L' D' 2F2 U2 Lw'
16 HTM · 12 STM · 22 QTM
rotationless
<U,F,D,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: U 3Lw D2 2L' D' 2R2 D 2L D' 2R2 D' 3Lw' U'. Every algorithm above was run by our logic engine from that state and reaches "solved".