VW
Algorithms (3)
D' 2R2 U' 2L2 U 2R2 U' 2L2 U D
My choice
14 HTM · 10 STM · 22 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
3Dw' 2R2 U' 2L2 U 2R2 U' 2L2 U 3Dw
14 HTM · 10 STM · 22 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
Cubemuch
D' 2R2 3Uw' 2L2 3Uw 2R2 3Uw' 2L2 3Uw D
14 HTM · 10 STM · 22 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3Dw' U' 2L2 U 2R2 U' 2L2 U 2R2 3Dw. Every algorithm above was run by our logic engine from that state and reaches "solved".