KV
Algorithms (3)
2D2 2R2 U' 2L U 2R2 U' 2L' U 2D2
My choice
16 HTM · 10 STM · 24 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 3 solvers' sheets
F2 2R2 U' 2L' U 2R2 U' 2L U F2
14 HTM · 10 STM · 20 QTM
rotationless
<U,R,F,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
2F 2D' 2F U2 2F' 2D 2F U2 2F2
16 HTM · 9 STM · 20 QTM
3-gen
rotationless
<U,F,D>
One hand: R, U and M with F and D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: F2 U' 2L' U 2R2 U' 2L U 2R2 F2. Every algorithm above was run by our logic engine from that state and reaches "solved".