KU
Algorithms (3)
U2 D' 2L2 U' 2R U 2L2 U' 2R' D U'
My choice
15 HTM · 11 STM · 20 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 4 solvers' sheets
F' U' 2L2 U 2R U' 2L2 U 2R' F
14 HTM · 10 STM · 18 QTM
rotationless
<U,R,F,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
x U' 2R' U' 2L' U 2R U' 2L U2 x'
13 HTM · 9 STM · 14 QTM
3-gen
rotation
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: F' 2R U' 2L2 U 2R' U' 2L2 U F. Every algorithm above was run by our logic engine from that state and reaches "solved".