JM
Algorithms (3)
F' 2L' U' 2L 2U 2L' U 2L 2U' F
My choice
16 HTM · 10 STM · 16 QTM
3-gen
rotationless
<U,F,L>
One hand: needs L, B, S or E
BLDDB, on 6 solvers' sheets
U' Rw U 2R' 2U 2R U' 2R' 2U' R' U
16 HTM · 11 STM · 16 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
BLDDB, on 1 solver's sheet
2R2 U' 2F U 2R U' 2F' U 2R
14 HTM · 9 STM · 16 QTM
3-gen
rotationless
<U,R,F>
One hand: R, U and M with F or D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: U' R 2U 2R U 2R' 2U' 2R U' Rw' U. Every algorithm above was run by our logic engine from that state and reaches "solved".