JL
Algorithms (3)
F2 2L 2B2 2L' F2 2L 2B2 2L'
My choice
14 HTM · 8 STM · 20 QTM
3-gen
rotationless
<F,L,B>
One hand: needs L, B, S or E
Cubemuch
3Lw 2B2 Dw 2R Dw' 2B2 Dw 2R' Dw' 3Lw'
14 HTM · 10 STM · 18 QTM
rotationless
<R,D,L,B>
One hand: needs L, B, S or E
Cubemuch
Lw 2B2 3Dw 2R 3Dw' 2B2 3Dw 2R' 3Dw' Lw'
14 HTM · 10 STM · 18 QTM
rotationless
<R,D,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3Lw Dw 2R Dw' 2B2 Dw 2R' Dw' 2B2 3Lw'. Every algorithm above was run by our logic engine from that state and reaches "solved".