DC
Algorithms (3)
3Lw U' 2R 2D2 2R' U 2R 2D2 2R' 3Lw'
My choice
16 HTM · 10 STM · 20 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
3Fw2 U' 2L2 U 2R2 U' 2L2 U 2R2 3Fw2
14 HTM · 10 STM · 24 QTM
rotationless
<U,R,F,L>
One hand: needs L, B, S or E
Cubemuch
Fw2 U' 2L2 U 2R2 U' 2L2 U 2R2 Fw2
14 HTM · 10 STM · 24 QTM
rotationless
<U,R,F,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3Fw2 2R2 U' 2L2 U 2R2 U' 2L2 U 3Fw2. Every algorithm above was run by our logic engine from that state and reaches "solved".