DA
Algorithms (3)
3Fw' U 2B' 2D2 2B U' 2B' 2D2 2B 3Fw
My choice
16 HTM · 10 STM · 20 QTM
rotationless
<U,F,D,B>
One hand: needs L, B, S or E
Cubemuch
Rw2 U 2R2 U' 2F2 U 2R2 U' 2F2 Rw2
14 HTM · 10 STM · 24 QTM
3-gen
rotationless
<U,R,F>
One hand: R, U and M with F or D
Cubemuch
3Lw2 3Dw 2R2 3Dw' 2B2 3Dw 2R2 3Dw' 2B2 3Lw2
14 HTM · 10 STM · 24 QTM
rotationless
<R,D,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: Rw2 2F2 U 2R2 U' 2F2 U 2R2 U' Rw2. Every algorithm above was run by our logic engine from that state and reaches "solved".