XK
Algorithms (3)
D2 U 3L' U' 2R2 U 3L U' 2R2 D2
My choice
14 HTM · 10 STM · 20 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 3 solvers' sheets
2R' F' 2R 3F2 2R' F 2R 3F2
14 HTM · 8 STM · 18 QTM
2-gen
rotationless
<R,F>
One hand: R, U and M with F or D
BLDDB, on 1 solver's sheet
U 3R U 2L2 U' 3R' U 2L2 U2
13 HTM · 9 STM · 18 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3F2 2R' F' 2R 3F2 2R' F 2R. Every algorithm above was run by our logic engine from that state and reaches "solved".