XJ
Algorithms (3)
D' 2R U 3L2 U' 2R' U 3L2 U' D
My choice
14 HTM · 10 STM · 18 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
D 2R U' 3L2 U 2R' U' 3L2 U D'
14 HTM · 10 STM · 18 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
Dw 2R Dw' 3F2 Dw 2R' Dw' 3F2
12 HTM · 8 STM · 16 QTM
3-gen
rotationless
<R,F,D>
One hand: R, U and M with F and D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: D U' 3L2 U 2R U' 3L2 U 2R' D'. Every algorithm above was run by our logic engine from that state and reaches "solved".