TV
Algorithms (3)
D' U' 3L2 U 2R' U' 3L2 U 2R D
My choice
14 HTM · 10 STM · 18 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
D2 2L' 3D2 2L' U2 2L 3D2 2L' U2 2L2 D2
18 HTM · 11 STM · 28 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
D U 3R2 U' 2R' U 3R2 U' 2R D'
14 HTM · 10 STM · 18 QTM
3-gen
rotationless
<U,R,D>
One hand: R, U and M with F or D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: D2 2L2 U2 2L 3D2 2L' U2 2L 3D2 2L D2. Every algorithm above was run by our logic engine from that state and reaches "solved".