TU
Algorithms (3)
U' 3L2 U 2R' U' 3L2 U 2R
My choice
12 HTM · 8 STM · 16 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 4 solvers' sheets
U' 3R2 U 2R' U' 3R2 U 2R
12 HTM · 8 STM · 16 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
Cubemuch
2R B' 3L B 2R' B' 3L' B
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<R,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 2R' U' 3R2 U 2R U' 3R2 U. Every algorithm above was run by our logic engine from that state and reaches "solved".