SF
Algorithms (3)
3D 2R U' 3L U 2R' U' 3L' U 3D'
My choice
16 HTM · 10 STM · 16 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
y' L' 3D 2R U 2R' 3D' 2R U' 2R' L y
16 HTM · 10 STM · 16 QTM
rotation
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
3Uw' U 2R U' 3R' U 2R' U' 3R 3Uw
14 HTM · 10 STM · 14 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: y' L' 2R U 2R' 3D 2R U' 2R' 3D' L y. Every algorithm above was run by our logic engine from that state and reaches "solved".