SE
Algorithms (3)
3L U' 3L 2U' 3L' U 3L 2U 3L2
My choice
16 HTM · 9 STM · 18 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
2U B2 2U' 3F' 2U B2 2U' 3F
14 HTM · 8 STM · 16 QTM
3-gen
rotationless
<U,F,B>
One hand: needs L, B, S or E
Cubemuch
3F 2R Bw 2R' 3F' 2R Bw' 2R'
14 HTM · 8 STM · 14 QTM
3-gen
rotationless
<R,F,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3F' 2U B2 2U' 3F 2U B2 2U'. Every algorithm above was run by our logic engine from that state and reaches "solved".