MD
Algorithms (3)
U 3L 2U 3L' U2 3L 2U' 3L' U
My choice
15 HTM · 9 STM · 16 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 3 solvers' sheets
U' 3L' 2U' 3L U2 3L' 2U 3L U'
15 HTM · 9 STM · 16 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
2U 3F 2U' 3F' U2 3F 2U 3F' 2U' U2
18 HTM · 10 STM · 20 QTM
2-gen
rotationless
<U,F>
One hand: R, U and M with F or D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: U 3L' 2U' 3L U2 3L' 2U 3L U. Every algorithm above was run by our logic engine from that state and reaches "solved".