MC
Algorithms (3)
3L' 2U' 3L U 3L' 2U 3L U'
My choice
14 HTM · 8 STM · 14 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 17 solvers' sheets
3R 2U' 3R' U 3R 2U 3R' U'
14 HTM · 8 STM · 14 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
Cubemuch
U R' 2F R 3F R' 2F' R 3F' U'
14 HTM · 10 STM · 14 QTM
3-gen
rotationless
<U,R,F>
One hand: R, U and M with F or D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: U 3R 2U' 3R' U' 3R 2U 3R'. Every algorithm above was run by our logic engine from that state and reaches "solved".