KU
Algorithms (3)
D 2R2 U 3L' U' 2R2 U 3L U' D'
My choice
14 HTM · 10 STM · 18 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
D 2R2 U 3R U' 2R2 U 3R' U' D'
14 HTM · 10 STM · 18 QTM
3-gen
rotationless
<U,R,D>
One hand: R, U and M with F or D
Cubemuch
F' 2R' F' 3L' F 2R F' 3L F2
13 HTM · 9 STM · 14 QTM
3-gen
rotationless
<R,F,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: D U 3R U' 2R2 U 3R' U' 2R2 D'. Every algorithm above was run by our logic engine from that state and reaches "solved".