KT
Algorithms (3)
2R' U 3L' U' 2R U 3L U'
My choice
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
F 2L' U2 2L 3D2 2L' U2 2L 3D2 F'
16 HTM · 10 STM · 22 QTM
rotationless
<U,F,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
2R' U 3R U' 2R U 3R' U'
12 HTM · 8 STM · 12 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: F 3D2 2L' U2 2L 3D2 2L' U2 2L F'. Every algorithm above was run by our logic engine from that state and reaches "solved".