L (FR)
OLL parity (1 flip)
2 Corners
Count the flipped dedges (one here), then read the corner shape as for OLL.
Your status
Algorithms (5)
(U') first, then:
U R' U' R Rw2 B2 U2 Lw U2 Rw' U2 Rw U2 F2 Rw F2
Lw' B2 Rw2 R' U R
My choice
22 HTM · 22 STM · 32 QTM
rotationless
<U,R,F,L,B>
One hand: needs L, B, S or E
Do U' first (AUF) on the case as drawn. · Cubemuch
R' U' R Rw U2 x Rw U2 Rw U2 Rw' U2 Lw U2 Rw' U2
Rw U2 Rw' U2 Rw' R' U R
23 HTM · 23 STM · 31 QTM
3-gen
rotation
<U,R,L>
One hand: needs L, B, S or E
Cubemuch
(U') first, then:
L' U' L U' L' U2 L Rw U2 x Rw U2 Rw U2 Rw' U2
Lw U2 Rw' U2 Rw U2 Rw' U2 Rw'
24 HTM · 24 STM · 33 QTM
3-gen
rotation
<U,R,L>
One hand: needs L, B, S or E
Do U' first (AUF) on the case as drawn. · Cubemuch
(U) first, then:
Rw' U Rw2 U Rw2 U2 Rw U2 Rw' U2 Rw U Rw U Rw U2
Rw' U2 Rw' U2 Rw2 U' Rw2 U Rw'
25 HTM · 25 STM · 35 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
Do U first (AUF) on the case as drawn. · Cubemuch
(U') first, then:
R B R' R 2R R 2R B2 2R' R' U2 2R' R' U2 B2 2R'
R' B2 R 2R B2 2R' R' B2 R 2R R 2R B2 U2 R B'
R'
42 HTM · 33 STM · 51 QTM
3-gen
rotationless
<U,R,B>
One hand: needs L, B, S or E
Do U' first (AUF) on the case as drawn. · Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: R' U' R Rw U2 Rw U2 Rw' U2 Rw U2 Lw' U2 Rw U2 Rw' U2 Rw' x' U2 Rw' R' U R. Every algorithm above was run by our logic engine from that state and reaches "oll-solved", keeping first-layers.