L (BL)
OLL parity (1 flip)
2 Corners
Count the flipped dedges (one here), then read the corner shape as for OLL.
Your status
Algorithms (5)
U2 B' R2 Rw2 B2 Rw' U2 Rw' U2 x' U2 Rw' U2 Rw U2 Rw'
U2 Rw2 U2 x U2 R2 B
My choice
21 HTM · 21 STM · 35 QTM
3-gen
rotation
<U,R,B>
One hand: needs L, B, S or E
Cubemuch
U2 Rw2 B2 U2 Lw U2 Rw' U2 Rw U2 F2 Rw F2 Lw' B2 Rw2
R' U' R U' R' U2 R
23 HTM · 23 STM · 35 QTM
rotationless
<U,R,F,L,B>
One hand: needs L, B, S or E
Cubemuch
(U2) first, then:
Rw U2 x Rw U2 Rw U2 Rw' U2 Lw U2 Rw' U2 Rw U2 Rw'
U2 Rw' R' U' R U' R' U2 R
24 HTM · 24 STM · 33 QTM
3-gen
rotation
<U,R,L>
One hand: needs L, B, S or E
Do U2 first (AUF) on the case as drawn. · Cubemuch
U' L' U2 L U' Rw2 B2 U2 Lw U2 Rw' U2 Rw U2 F2 Rw
F2 Lw' B2 Rw2 U L' U2 L
24 HTM · 24 STM · 36 QTM
rotationless
<U,R,F,L,B>
One hand: needs L, B, S or E
Cubemuch
(U2) first, then:
B' R2 R 2R R 2R B2 2R' R' U2 2R' R' U2 B2 2R' R'
B2 R 2R B2 2R' R' B2 R 2R R 2R B2 U2 R2 B
40 HTM · 31 STM · 51 QTM
3-gen
rotationless
<U,R,B>
One hand: needs L, B, S or E
Do U2 first (AUF) on the case as drawn. · Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: R' U2 R U R' U R Rw2 B2 Lw F2 Rw' F2 U2 Rw' U2 Rw U2 Lw' U2 B2 Rw2 U2. Every algorithm above was run by our logic engine from that state and reaches "oll-solved", keeping first-layers.