PE
Algorithms (3)
R 2U 2L' U' 2L 2U2 2L' U 2L 2U R'
My choice
18 HTM · 11 STM · 20 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
2B' U 2F' U' 2B U 2F U'
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<U,F,B>
One hand: needs L, B, S or E
Cubemuch
2B' Dw 2R' Dw' 2B Dw 2R Dw'
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<R,D,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: U 2F' U' 2B' U 2F U' 2B. Every algorithm above was run by our logic engine from that state and reaches "solved".