PD
Algorithms (3)
U2 2R 2D 2R' U2 2R 2D' 2R'
My choice
14 HTM · 8 STM · 16 QTM
3-gen
rotationless
<U,R,D>
One hand: R, U and M with F or D
BLDDB, on 6 solvers' sheets
2L 2D' 2L' U2 2L 2D 2L' U2
14 HTM · 8 STM · 16 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 3 solvers' sheets
2L 2D' 2L' Uw2 2L 2D 2L' Uw2
14 HTM · 8 STM · 16 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: U2 2L 2D' 2L' U2 2L 2D 2L'. Every algorithm above was run by our logic engine from that state and reaches "solved".