JX
Algorithms (3)
D U' 2L2 U 2R U' 2L2 U 2R' D'
My choice
14 HTM · 10 STM · 18 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 7 solvers' sheets
2B2 Dw 2R Dw' 2B2 Dw 2R' Dw'
12 HTM · 8 STM · 16 QTM
3-gen
rotationless
<R,D,B>
One hand: needs L, B, S or E
Cubemuch
2B2 D 2R D' 2B2 D 2R' D'
12 HTM · 8 STM · 16 QTM
3-gen
rotationless
<R,D,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: Dw 2R Dw' 2B2 Dw 2R' Dw' 2B2. Every algorithm above was run by our logic engine from that state and reaches "solved".