JW
Algorithms (3)
D2 U' 2L2 U 2R U' 2L2 U 2R' D2
My choice
14 HTM · 10 STM · 20 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 5 solvers' sheets
Uw 2R2 Uw 2L Uw' 2R2 Uw 2L' Uw2
13 HTM · 9 STM · 18 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 3 solvers' sheets
Uw2 2L' B' 2R' B 2L B' 2R B Uw2
14 HTM · 10 STM · 16 QTM
rotationless
<U,R,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: Uw2 2L Uw' 2R2 Uw 2L' Uw' 2R2 Uw'. Every algorithm above was run by our logic engine from that state and reaches "solved".