KA
Algorithms (3)
R' F' 2U' R U R' 2U R U' R' F R
My choice
14 HTM · 12 STM · 14 QTM
3-gen
rotationless
<U,R,F>
One hand: R, U and M with F or D
BLDDB, on 17 solvers' sheets
2L' D2 2L U2 2L' D2 2L U2
12 HTM · 8 STM · 16 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 9 solvers' sheets
U R' U2 R U 2R U' R' U 2R' U R U'
15 HTM · 13 STM · 16 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
BLDDB, on 5 solvers' sheets
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: U2 2L' D2 2L U2 2L' D2 2L. Every algorithm above was run by our logic engine from that state and reaches "solved".