JX
Algorithms (3)
D' 2R2 U' R U 2R2 U' R' U D
My choice
12 HTM · 10 STM · 16 QTM
3-gen
rotationless
<U,R,D>
One hand: R, U and M with F or D
BLDDB, on 27 solvers' sheets
L F' 2U' L' U L 2U L' U' L F L'
14 HTM · 12 STM · 14 QTM
3-gen
rotationless
<U,F,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
L 2U2 L U L' 2U2 L U' L2
11 HTM · 9 STM · 16 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: L F' L' U L 2U' L' U' L 2U F L'. Every algorithm above was run by our logic engine from that state and reaches "solved".