Za / Pi L
L4C+CLL (Ranzha)
Za
Match the case drawing, including the side colours and the pieces already solved; hold the puzzle as drawn.
Your status
Algorithms (6)
(y) first, then:
x2 r x' b x b x' b' x r' x' b x b' x' b'
x'
My choice
8 HTM · 8 STM · 8 QTM
2-gen
rotation
<r,b>
Do y first on the case as drawn. · Cubemuch
x r x b x' R x b' x' r' x b x' R' x b'
x2
8 HTM · 8 STM · 8 QTM
3-gen
rotation
<r,b,R>
Cubemuch
(y) first, then:
x2 b' x' b x f x' b x f' b' x' b' x b' x'
b' x'
9 HTM · 9 STM · 9 QTM
2-gen
rotation
<b,f>
Do y first on the case as drawn. · Cubemuch
(y) first, then:
x2 b x' R' x b' x' R x' y z' x R' x b x'
R x b' x2 y2 x R' x b x' R x b' x2 y2 z
y'
12 HTM · 12 STM · 12 QTM
2-gen
rotation
<b,R>
Do y first on the case as drawn. · Cubemuch
x R r' R' r y z' r' R r R' z2 r' R r R'
z' y' x'
12 HTM · 12 STM · 12 QTM
2-gen
rotation
<r,R>
Cubemuch
(y2) first, then:
R r' R' b r' b f R'
8 HTM · 8 STM · 8 QTM
rotationless
<r,b,f,R>
Do y2 first on the case as drawn. · Cubemuch
How this case is verified
The source's case image defines this case; its setup is reconstructed and checked against that independent pattern. Setup: y2 x2 b x' R x b' x' r x b x' R' x b' x' r' x'. Every algorithm above was run by our logic engine from that state and reaches "solved".