H / P FL
L4C+CLL (Ranzha)
H
Match the case drawing, including the side colours and the pieces already solved; hold the puzzle as drawn.
Your status
Algorithms (6)
x2 r' b' f' b' r' f b r' f x2
My choice
9 HTM · 9 STM · 9 QTM
3-gen
rotation
<r,b,f>
Cubemuch
x b x r' x' b x f x' b x f' r' x' b x
r x2
9 HTM · 9 STM · 9 QTM
3-gen
rotation
<b,r,f>
Cubemuch
(y) first, then:
x2 b x' R' x b' x' R x' y x R' x b x' R
x b' x' R' x b x' R x b' x2 y'
12 HTM · 12 STM · 12 QTM
2-gen
rotation
<b,R>
Do y first on the case as drawn. · Cubemuch
(y') first, then:
y2 x2 b x' R' x b' x' R x' y x R' x b x'
R x b' x' R' x b x' R x b' x2 y
12 HTM · 12 STM · 12 QTM
2-gen
rotation
<b,R>
Do y' first on the case as drawn. · Cubemuch
(y') first, then:
y x2 b x' R' x b' x' R x b x' R' x b' x'
R x' y x2 b x' R' x b' x' R x' y2
12 HTM · 12 STM · 12 QTM
2-gen
rotation
<b,R>
Do y' first on the case as drawn. · Cubemuch
(y2) first, then:
x r' x b x' R' x b' x' R' r' R' r R r' R'
r' x'
12 HTM · 12 STM · 12 QTM
3-gen
rotation
<r,b,R>
Do y2 first on the case as drawn. · Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: x2 r' x' b' x r f x' b' x f' x' b' x r x' b' x'. Every algorithm above was run by our logic engine from that state and reaches "solved".
Every listed algorithm is equivalent to the defining setup reversed under this set's permitted turns. The engine confirms it solves the case drawn, but the case's name rests on the source alone.