XR
Algorithms (3)
D' U2 2L U' 2R2 U 2L' U' 2R2 U' D
My choice
15 HTM · 11 STM · 20 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 5 solvers' sheets
U x' 2L U' 2R U 2L' U' 2R' U x U'
14 HTM · 10 STM · 14 QTM
3-gen
rotation
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
U 2L B' 2R B 2L' B' 2R' B U'
14 HTM · 10 STM · 14 QTM
rotationless
<U,R,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: U x' U' 2R U 2L U' 2R' U 2L' x U'. Every algorithm above was run by our logic engine from that state and reaches "solved".