XF
Algorithms (3)
2L2 U2 2L' 2U 2L U2 2L' 2U' 2L'
My choice
16 HTM · 9 STM · 20 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 5 solvers' sheets
U 2F U' 2B2 U 2F' U' 2B2
12 HTM · 8 STM · 16 QTM
3-gen
rotationless
<U,F,B>
One hand: needs L, B, S or E
Cubemuch
2B2 3Uw 2L' 3Uw' 2B2 3Uw 2L 3Uw'
12 HTM · 8 STM · 16 QTM
3-gen
rotationless
<U,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 2B2 U 2F U' 2B2 U 2F' U'. Every algorithm above was run by our logic engine from that state and reaches "solved".