XD
Algorithms (3)
2R U D 2L2 U 2R' U' 2L2 U 2R U2 D' 2R'
My choice
19 HTM · 13 STM · 24 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
U Rw' U' 2L2 U' 2R U 2L2 U' 2R' U2 Rw U'
17 HTM · 13 STM · 22 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
Rw' U D 2L2 U 2R U' 2L2 U 2R' D' U2 Rw
17 HTM · 13 STM · 22 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: U Rw' U2 2R U 2L2 U' 2R' U 2L2 U Rw U'. Every algorithm above was run by our logic engine from that state and reaches "solved".