WI
Algorithms (3)
D' U' 2L' U 2R2 U' 2L U 2R2 D
My choice
14 HTM · 10 STM · 18 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 6 solvers' sheets
3Dw' U' 2L' U 2R2 U' 2L U 2R2 3Dw
14 HTM · 10 STM · 18 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
Cubemuch
Dw' U' 2L' U 2R2 U' 2L U 2R2 Dw
14 HTM · 10 STM · 18 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3Dw' 2R2 U' 2L' U 2R2 U' 2L U 3Dw. Every algorithm above was run by our logic engine from that state and reaches "solved".