TE
Algorithms (3)
Uw' 2L' Uw 2R' Uw' 2L Uw 2R
My choice
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 6 solvers' sheets
3Uw' 2L' 3Uw 2R' 3Uw' 2L 3Uw 2R
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
Cubemuch
3Dw' 2B' 3Dw 2R' 3Dw' 2B 3Dw 2R
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<R,D,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 2R' 3Uw' 2L' 3Uw 2R 3Uw' 2L 3Uw. Every algorithm above was run by our logic engine from that state and reaches "solved".