SK
Algorithms (3)
2L U' 2L' 2D2 2L U 2L' 2D2
My choice
14 HTM · 8 STM · 18 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 5 solvers' sheets
F' 2R U' 2L U 2R' U' 2L' U F
14 HTM · 10 STM · 14 QTM
rotationless
<U,R,F,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
U' 2D2 2R U2 2R' 2D2 2R U2 2R' U
16 HTM · 10 STM · 22 QTM
3-gen
rotationless
<U,R,D>
One hand: R, U and M with F or D
BLDDB, on 1 solver's sheet
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: F' U' 2L U 2R U' 2L' U 2R' F. Every algorithm above was run by our logic engine from that state and reaches "solved".