SF
Algorithms (3)
2U' 2R U' 2L U 2R' U' 2L' Uw
My choice
14 HTM · 9 STM · 14 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 4 solvers' sheets
Lw U' 2L' 2D' 2L U 2L' 2D L'
14 HTM · 9 STM · 14 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
L' 2B' 2R B 2R' 2B 2R B' 2R' L
16 HTM · 10 STM · 16 QTM
3-gen
rotationless
<R,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: L 2D' 2L U' 2L' 2D 2L U Lw'. Every algorithm above was run by our logic engine from that state and reaches "solved".