RJ
Algorithms (3)
2L U2 2L' 2U2 2L U2 2L' 2U2
My choice
14 HTM · 8 STM · 20 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 7 solvers' sheets
U' 2U2 2R U 2R' 2U2 2R U' 2R' U
16 HTM · 10 STM · 20 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
BLDDB, on 1 solver's sheet
2U' 2F U 2F' 2U2 2F U' 2F' 2U'
16 HTM · 9 STM · 18 QTM
2-gen
rotationless
<U,F>
One hand: R, U and M with F or D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: U' 2R U 2R' 2U2 2R U' 2R' 2U2 U. Every algorithm above was run by our logic engine from that state and reaches "solved".