QE
Algorithms (3)
U' 2R' U2 2R 2U 2R' U2 2R 2U' U
My choice
16 HTM · 10 STM · 18 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
BLDDB, on 4 solvers' sheets
2U2 2L' U' 2L 2U 2L' U 2L 2U
16 HTM · 9 STM · 18 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
2U' R' 2B R 2U R' 2B' R
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<U,R,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 2U' 2L' U' 2L 2U' 2L' U 2L 2U2. Every algorithm above was run by our logic engine from that state and reaches "solved".