PN
Algorithms (3)
2D 2R 2D' R2 2D 2R' 2D' R2
My choice
14 HTM · 8 STM · 16 QTM
2-gen
rotationless
<R,D>
One hand: R, U and M with F or D
Cubemuch
R2 2U 2R' 2U' R2 2U 2R 2U'
14 HTM · 8 STM · 16 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
Cubemuch
R 2F 2R2 2F' R2 2F 2R2 2F' R
15 HTM · 9 STM · 20 QTM
2-gen
rotationless
<R,F>
One hand: R, U and M with F or D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 2U 2R' 2U' R2 2U 2R 2U' R2. Every algorithm above was run by our logic engine from that state and reaches "solved".