PI
Algorithms (3)
Dw U' 2L' U 2R' U' 2L U 2R Dw'
My choice
14 HTM · 10 STM · 14 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 4 solvers' sheets
R 2U 2L' U' 2L 2U' 2L' U 2L R'
16 HTM · 10 STM · 16 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 3 solvers' sheets
Uw' R 2U 2L 2U' R' 2U 2L' U
14 HTM · 9 STM · 14 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: R 2L' U' 2L 2U 2L' U 2L 2U' R'. Every algorithm above was run by our logic engine from that state and reaches "solved".