PC
Algorithms (3)
U' 2R 2D 2R' U 2R 2D' 2R'
My choice
14 HTM · 8 STM · 14 QTM
3-gen
rotationless
<U,R,D>
One hand: R, U and M with F or D
BLDDB, on 20 solvers' sheets
Rw 2U' 2R' U 2R 2U 2R' U' R'
14 HTM · 9 STM · 14 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
BLDDB, on 1 solver's sheet
2F' 2R B 2R' 2F 2R B' 2R'
14 HTM · 8 STM · 14 QTM
3-gen
rotationless
<R,F,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: R U 2R 2U' 2R' U' 2R 2U Rw'. Every algorithm above was run by our logic engine from that state and reaches "solved".